//If limit is 2 then output will 5*1=5 \n 5*2=10
#include <stdio.h>
#include <conio.h>
void main()
{
int n,i,m;
clrscr();
printf("Enter limitation of this calculation: ");
scanf("%d",&n);
for(i=0;n>=i;i++)
{
m=5*i;
printf("5*%d=%d\n",i,m);
}
getch();
}
#include <stdio.h>
#include <conio.h>
void main()
{
int n,i,m;
clrscr();
printf("Enter limitation of this calculation: ");
scanf("%d",&n);
for(i=0;n>=i;i++)
{
m=5*i;
printf("5*%d=%d\n",i,m);
}
getch();
}
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